A(1,2),B(7,3),C(8,9) and D(2,8)are the vertices of a quadrilateral. Provr that ABCD is not a square.
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distance of ab is √37 and BC is √37 and cd is √37 and da is √37 and here all sides are equal so now we should check now diagonals AC is √98 and BD is √50 so here diagonal are not equal so it is not a square it is a rhombus
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