Math, asked by Anonymous, 1 year ago

A 1.2 m tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m from the ground.the angle of elevation of the balloon from the eye of the girl at any instant is 60°. After some time,the angle of elevation reduces to 30°. Find the distance traveled by the balloon during the interval.

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Answered by SahilChandravanshi

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Answered by santy2

Answer:

Step-by-step explanation:

This is a question on Trigonometry.

The height of the right angled triangle formed is :

88.2 - 1.2 = 87m

That is in the difference between the height of the girl and the balloon.

We need to get the horizontal distance when the angle of elevation is 60°.

We use the trigonometric ratios.

We use Tan.

Tan = opposite / adjacent

Opposite = height = 87m

Opposite = Horizontal distance.

Now :

Tan 60 = 87/H

H = 87/Tan 60 = 50.229 M

When the angle of elevation is 30°

H = 87/Tan 30 = 150.688M

The distance traveled is the difference between the two distances.

150.688 - 50.229 = 100.459 M

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