a 1/2 PQ b1/2 RS c1/2 PQ+RS d1/2 PQ+RS XY=
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Answer:
Given that Area of the Δ APQ = Area of PQCB
That means Area Δ ABC = 2 Area of Δ APQ
Since PQ ∥ BC
Therefore, Δ APQ is similar to Δ ABC
We know that ratio of the areas of two triangles is equal to the square of ratio of their sides in case of similar triangles.
Therefore,
Areaof△ABC
Areaof△APQ
=
AB
2
PA
2
AB
2
PA
2
=
Areaof△ABC
Areaof△APQ
=
2
1
AB
PA
=
2
1
Therefore, PA:AB = 1:
2
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