Question

A 1.2g/l of solution of NaCl is isotonic with 7.2g/l of solution of glucose.Calculate the vant hoff factor of NaCl solution
a. 2.36
b.1.50
c. 1.95
d. 1.00

Answer 1

Answer:

ANSWER

The molar masses of NaCl and glucose are 58.5 g/mol and 180 g/mol respectively.

The expression for the osmotic pressure is as follows:

Π=iCRT

Since two solutions are isotonic, they have equal osmotic pressure.

Π(NaCl)=Π(glucose)

i(NaCl)C(NaCl)=i(glucose)C(glucose)

i(NaCl)×

58.5

1.2

=1×

180

7.2

i(NaCl)=1.95

Let α be the degree of ionization of NaCl.

α=

n

′

−1

i−1

=

2−1

1.95−1

=0.95

Here, n

′

represents the total number of ions produced by dissociation of one molecule of NaCl.

Answer 2

Answer:

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