a=1/3-2√2, b=1/3+2√2 show that a square b+ab square=6
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a=1/3-2√2, b=1/3+2√2 show that a square b+ab square=6
=1/3+2 (2^1/2) +1/3-2(2^1/2)
=1/3+8^1/2/3 + 1-8^1/2/3(1-8^1/2/3 (here we should a^2-b^2)
=1+8^1/2/3 + (1-8^1/2/3)×(1+8^1/2/3)
=1+8^1/2/3 +1-8/3
=1+8^1/2+1-8/3
= -6+8^1/2/3
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