a = (1+√3+√2), then the value of (2a4-8a³-5a² +26a-28)ans plz
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Correct Question
a = (1+√3+√2), then the value of 2a⁴-8a³-5a² +26a-28
Answer
The answer is 6√6
Given
a = 1 + √3 + √2
To Find
Value of 2a⁴-8a³-5a² +26a-28
Solution
a = 1 + √3 + √2
a² = (1 + √3 + √2)²
We know that (x + y + z)² = x² + y² + z² + 2xy + 2xz + 2yz
Therefore applying this we get
= 1² + √3² + √2² + 2(√3 X 1) + 2(√2 X 1) + 2(√3 X √2)
= 1 + 3 + 2 + 2√3 + 2√2 + 2√6
= 6 + 2√3 + 2√2 + 2√6
a³ = a X a²
= (4 + 2√3 + 2√2 + 2√6)( 1 + √3 + √2)
= 6 + 6√3 + 6√2 + 6√3 + 6 + 2√6 + 2√2 + 2√6 + 4 + 2√6 + 2√18 + 2√12
We know that √18 = 3√2 and √12 = 2√3. Using this here we get,
= 6 + 6√3 + 6√2 + 6√3 + 6 + 2√6 + 2√2 + 2√6 + 4 + 2√6 + 26√3 + 4√3
= 16 + 12√3 + 14√2 + 6√6
a⁴ = (a)²
= (6 + 2√3 + 2√2 + 2√6)²
We know that
(p + q + r + s)² = p² + q² + r² + s² + 2pq + pr + 2ps + 2qr + 2rs
Therefore, by applying this we get
6² + (2√3)² + (2√2)² + (2√6)² + 24√3 + 24√2 + 24√6 + 2(2√3 X 2√2) + 2(2√3 X 2√6) + 2(2√2 X 2√6)
= 36 + 12 + 8 + 24 + 24√3 + 24√2 + 24√6 + 8√6 + 8√18 + 8√12
= 80 + 24√3 + 24√2 + 24√6 + 8√6 + 24√2 + 16√3
= 80 + 40√3 + 48√2 + 32√6
2a⁴-8a³-5a² +26a-28
= 2(80 + 40√3 + 48√2 + 32√6) - 8(16 + 12√3 + 14√2 + 6√6)
- 5(6 + 2√3 + 2√2 + 2√6) + 26( 1 + √3 + √2) + 28
= 160 + 80√3 + 96√2 + 64√6
-128 - 96√3 - 112√2 - 48√6
-30 - 10√3 - 10√2 - 10√6
+ 26 + 26√3 + 26√2
- 28
= 0 + 0 + 0 + 6√6
= 6√6
Therefore, the answer is 6√6
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