Question

A 1/3+b1/3+c1/3 =0 then (a+b+c)3

Answer 1

HERE

a1/3+b1/3+c1/3 =0

or,(3a+1)/3+(3b+1)/3+(3c+1)/3=0

or,(3a+1+3b+1+3c+1)/3=0

or,3a+3b+3c+3=0

or,3(a+b+c)=-3

a+b+c=-1