(a) 1 = 3 cm; b=2 cm, h=1 cm answer should be LSA =10sq cm;TSA =22sq cm
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Step by step explanation
given: l = 3 cm , b = 2cm and h = 1cm
to find : LSA and TSA of a cubiod
LSA of a cubiod = 2h(l+b) sq.units
= 2(3+2)
= 2(5)
= 10 sqcm
TSA of a cubiod = 2(lb+ bh+ hl) sq. units
= 2(3×2 + 2×1 +1×3)
=2( 6+ 2+ 3)
=2(11)
= 22 sq cm
therefore LSA = 10 sq cm ; TSA = 22 sq cm
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