(a) 1.34: A lorry moving under uniform acceleration covers a distance of 180 m from point A
to point B along a straight path in 15 s. Its velocity, while passing through point B, is 20 m st.
(a) What is the velocity of the lorry at the time of passing through point A?
(b) What is its acceleration?
S
Answers
Answered by
1
Answer:
It's Velocity at the time of passing A is 0m/s (starting from A)
We need to find out the rate at which the lorry accelerated so that it goes from 0m/s to 20m/s
We know that v=u+at
20=0+ta
20=ta
20=15a
20/15=a
4/3=a
1.3 m/s^2=a
There you go, the acceleration is 1.3 metres/second square.
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Explanation:
Answered by
2
Answer:
Answer:
It's Velocity at the time of passing A is 0m/s (starting from A)
We need to find out the rate at which the lorry accelerated so that it goes from 0m/s to 20m/s
We know that v=u+at
20=0+ta
20=ta
20=15a
20/15=a
4/3=a
1.3 m/s^2=a
There you go, the acceleration is 1.3 metres/second square.
Hope this helped, mark as BRAINLIEST to help he reach the 'Expert' rank!
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