Question

a+1‚3a‚4a+2 are in Ap find a

Answer 1

Hence a2 - a1 = a3 - a2

3a-a-1=4a+2-3a

2a-1=a+2

2a-2=2+1

a=3

Answer 2

Given :

a+1‚3a‚4a+2 are in Ap

To Find :

Find a

Solution:

AP:a+1‚3a‚4a+2

$a_1=a+1$

$a_2=3a$

$a_3=4a+2$

Common difference :

= $a_2-a_1=a_3-a_2$

Substitute the values :

So, 3a-a-1=4a+2-3a

2a-1=a+2

2a-a=2+1

a=3

Hence The value of a is 3