Question

A=[1,4,5,9,11,12] B=[1,4,5,6,7,8,10,13] Verify n( AUB)+n(AnB)=n(A)+n(B)​

Answer 1

Answer:

Given :

A = [1,4,5,9,11,12]

B=[1,4,5,6,7,8,10,13]

So, n (A) = 6

n (B) = 8

n (AnB) = 3, where n is intersection.

Therefore, n (AUB) = n (A) + n (B) - n (AnB)

= 6 + 8 - 3 = 14 -3 = 11

Now, Taking LHS = n( AUB)+n(AnB)

= 11 + 3 = 14

And, Taking RHS = n(A)+n(B)

= 6 + 8 = 14

At last, LHS = RHS . Hence, verified.