A(1,-4),B(3,2)and C(-1,2)are the vertices of Triangle ABC and D is the mid point of BC. If P is a point on AD such that AP/PD=2/1,then find the coordinates of P.
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A(1,-4) B(3,2) C(-1,2) D(x, y)
x = x↓2 + x↓1 / 2
= -1 + 3 / 2
x = 1
y = y↓2 + y↓1 / 2
= 2 + 2 / 2
y = 2
D(1,2)
A(1,-4) B(3,2) C(-1,2) P(x, y)
x = m↓1x↓2 + m↓2x↓1 / 2
= 2 × 2 + 1 × 1 / 3
x = 1
y = m↓1y↓2 + m↓2y↓1 / 2
= 2 × 2 + 1 × -1 /2
y = 0
Coordinate is P(1,0)
please put in brainlist
x = x↓2 + x↓1 / 2
= -1 + 3 / 2
x = 1
y = y↓2 + y↓1 / 2
= 2 + 2 / 2
y = 2
D(1,2)
A(1,-4) B(3,2) C(-1,2) P(x, y)
x = m↓1x↓2 + m↓2x↓1 / 2
= 2 × 2 + 1 × 1 / 3
x = 1
y = m↓1y↓2 + m↓2y↓1 / 2
= 2 × 2 + 1 × -1 /2
y = 0
Coordinate is P(1,0)
please put in brainlist
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