Question

a 1.4cm long object is placed perpendicular to the principal axis of a convex mirror of focal length 15cm at a distance of 10cm from it calculate the location of the image,
height of the image ,
nature of the image​

Answer 1

Explanation:

given, convex mirror so focal length is positive so f=15cm by cartisan sign rule.

object u=-10cm due to cartisan rule

applying mirror formula

1/f = 1/V+1/u

1/15= 1/V - 1/10

1/15+1/10 = 1/V

1/6=1/V

V=6cm

where V is position of image

by magnification formula

m=-V/u = -hi/ho

=> V/u = hi/ho

=> 6/10 = hi/140. (1.4 m = 140cm)

=> hi = 84cm here hi is height of image. CHEERS DUDE

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Answer 2

Explanation:

hope the answer is correct