A(1,-5) , B(2,2) , C(-2,4) are the vertices of triangle ABC. Find the equation of :
1. The median through A
2. The altitude through B and
3.The line through C and parallel to AB
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8x + y = 3 is The median through A , 3y = x + 4 is The altitude through B and y = 7x + 18 is The line through C and parallel to AB if A(1,-5) , B(2,2) , C(-2,4) are the vertices of triangle
Step-by-step explanation:
A(1,-5) , B(2,2) , C(-2,4)
Mid point of BC = (2 -2)/2 , (2 + 4)/2
= (0 , 3)
A = (1 , - 5)
Slope = (-5 - 3)/(1 - 0) = - 8
y = -8x + c
3 = 0 + c
=> y = -8x + 3
=> 8x + y = 3
8x + y = 3 is The median through A
Slope of AC = (4 -(-5))/(-2 - 1) = -3
Slope of . The altitude through B = 1/3
y = x/3 + c
2 = 2/3 + c
=> c = 4/3
y = x/3 + 4/3
=> 3y = x + 4 is The altitude through B
Slope of AB = 7
y = 7x + c
passes through C
=> 4 = -14 + c
=> c = 18
=> y = 7x + 18 is The line through C and parallel to AB
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