Question

A 1.5 m high person is holding a 20 kg trunk on his head and is standing at a roadways bus-terminal. How much work is done by the person?

Answer 1

Answer:

Explanation:

Given :

• Height (h) = 1.5 m
• Mass (m) = 20 kg
• Acceleration due to gravity (g) = 10 ms²

To Find :

• Work done by the person, W

Formula to be used :

• W = mgh

Solution :

★Work done by the person,

W = mgh

⇒ W = 20 × 10 × 1.5

⇒ W = 20 × 15

⇒ W = 300 J

Hence, Work done by the person is 300 J.

Know to more:

• K.E = ¹/2 × mv²
• P.E = mgh
• M.E = P.E + K.E

Answer 2

$\huge\mathcal\colorbox{black}{{\color{white}{★ANSWER★}}}$

$\huge\color{black}{\textbf{\textsf{GIVEN :-}}}$

• Height (h) = 1.5 m
• Mass (m) = 20 kg
• Acceleration due to gravity (g) = 10 ms²

$\huge\color{black}{\textbf{\textsf{TO FIND :-}}}$

• The work done by the person (W).

$\huge\color{black}{\textbf{\textsf{FORMULA :-}}}$

• W = mgh

$\huge\color{black}{\textbf{\textsf{SOLUTION :-}}}$

W = mgh

→ W = 20 × 10 × 1.5

→ W = 20 × 15

→ W = 300 J

Hence, the work done by the person is 300 J.

Hope it Helps Buddy ♥️