Question

A 1.5 m tall bout is standing at some distance from a 30m tall buildings. The angle of elevation from his eye to the top of the building increases from 30to 60 as he walks towards the building. Find the distance he walked towards the building

Answer 1

Answer:

at 1st cond

tan Ф=building h/distance from building

tan 30=30/d

d=30√3

at sec cond

tan Ф=building h/final distane from building after he moved

tan 60=30/x

x=30/√3

dist he moved =d-x=(30√3)-(30/√3)

                                =60/√3=20√3

Step-by-step explanation: