A 1.5 m tall boy is standing at some distance from a 30 m tall building. The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building. Find the distance he walked towards the building. please don't spam here if anyone spam here I will repot his/her answer.
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Step-by-step explanation:
REF.Image
AB= 30-1.5=28.5 cm
In ΔABD:−tan30
∘
=
BD
AB
⇒BD=(28.5)
3
In ΔABC:−tan60
∘
=
BC
AB
⇒BC=
3
(28.5)
CD= BD-BC
=28.5(
3
−
3
1
)
=28.5(
3
2
)=32.91m
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