a 1.5 m
wide foothpath runs all along the fence . outside a park 40 m long and 30 m wide what is the perimeter of the fence and what is the area of the footpath.
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Answered by
180
The length of park= 40 m
The breadth of the park= 30m
The length of outer rectangle(path and park)=40+1.5+1.5=43m
The breadth of outer rectangle=30+1.5+1.5=33m
The perimeter of the fence=2(40+30)=2*70m=140m
THe area of outer rectangle=43m * 33m=1419 m2
the area of the park= 40m * 30m= 1200m2
The area of the path= 1419-1200
219 m2
Hope this will help you...Plz mark it as brainliest...
The breadth of the park= 30m
The length of outer rectangle(path and park)=40+1.5+1.5=43m
The breadth of outer rectangle=30+1.5+1.5=33m
The perimeter of the fence=2(40+30)=2*70m=140m
THe area of outer rectangle=43m * 33m=1419 m2
the area of the park= 40m * 30m= 1200m2
The area of the path= 1419-1200
219 m2
Hope this will help you...Plz mark it as brainliest...
Answered by
13
Thanks
please make it brainlist answer
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