Question

a 1.5 metre wide Footpath runs along the fans outside a Paak of 40 m long and 30 metre wide what is the perimeter of the fence and what is the area of the footpath​

Answer 1

The length of park= 40 m

The breadth of the park= 30m

The length of outer rectangle(path and park)=40+1.5+1.5=43m

The breadth of outer rectangle=30+1.5+1.5=33m

The perimeter of the fence=2(40+30)=2*70m=140m

THe area of outer rectangle=43m * 33m=1419 m2

the area of the park= 40m * 30m= 1200m2

The area of the path= 1419-1200

219 m2

Answer 2

Answer:

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$\bf \huge \: Question \: \:$

• A 1.5 metre wide Footpath runs along the fans outside a Paak of 40 m long and 30 metre wide what is the perimeter of the fence and what is the area of the footpath

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$\bf \huge \:To \: Find\:$

• what is the perimeter of the fence ?

• what is the area of the footpath ?

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$\bf \huge \:Given\: \:$

• The length of the park is 40m

• Breadth of the park is 30m.

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$\bf \: applying\: \: the\: \: Formula \: \: of \: \: area \: \:$

we have formula,

area of the park = l×b

Putting the value of l and b from formula

= 40×30

on multiplying

= 1200m²

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$\bf \huge \:Given\: \:$

if the 1.5m path runs outside the park all around, then the length of the path

parallel to the length of the park will be = 40+1.5+1.5

$\bf \huge\: on\: \: adding\: \:$

= 40+3

= 43m

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length of the parallel to the breadth of the park will be = 30+1.5+1.5

$\bf \huge\: on\: \: adding\: \:$

= 30+3

= 33m

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$\bf \: applying\: \: the\: \: Formula \: \: of \: \: area \: \:$

area of the park along with the path = l×b

Putting the value of l and b from formula

= 43×33

On multiplying

= 1419m²

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now,

area of the path = 1419-1200

on substation

= 219m²

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$\bf \: applying\: \: the\: \: Formula \: \: of \: \: perimeter\: fence \:$

perimeter of the fence = 2(l+b)

Putting the value of l and b from formula

= 2(40+30)

= 2×70

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On multiplying

= 140m

hence the perimeter of the fence is 140m

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