Question

(a) 1.5 s
(b)-S
13
)
17. When the speed of a car is , the minimum
distance over which it can be stopped is s. If the
speed becomes no, what will be the minimum
distance over which it can be stopped during
same time?
(a) s/n (b) ns (c) s/n (d) n²s

Answer 1

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✍ (d) n²s

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EXPLANATION —

Since we know

v² - u² =2as

for maximum retardation u must be zero

v² - 0 =2as

a = v²/2s is the max retardation

when the initial velocity is nv, then the distance over which it can be stopped is given by

=> $Sn= \frac{u0^{2} }{ 2a}$

= (nv) ²/ 2(v²/2s). = n²s

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Answer 2

Answer:

see the attached pictures!!!!