A 1.59 L sample of carbon monoxide was collected at 55 °C and 0.892 atm. What volume will the gas occupy at 1.05 atm and 20 °C? *
0.49 L
1.67 L
1.21 L
1.51 L
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here is the answer.
by P1V1/T1 = P2V2/T2
SO 0.892×1.59 / 328 = 1.05×V2 / 293
so, V2 = 0.892×1.59×293/328×1.05 litres.
hope it helps
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