Question

A 1.5kg hammer moving with a velocity of 10m/s strikes a nail for 0.005s.The average force exerted on the nail is​

Answer 1

Answer:

If a 1.5kg hammer moving with a velocity of 10m/s strikes a nail for 0.005s, then the average force exerted on the nail is​ 3000 N.

Explanation:

The force applied to an object is calculated by using the formula:

F=ma [Force = Mass × Acceleration of the object]

Here, the mass of the hammer given = 1.5 Kg.

We need to calculate the acceleration of the hammer.

Given that, the velocity of the hammer (v) = 10 m/s
and, the time of contact between the hammer and the nail (t) = 0.005 seconds.

∴ acceleration of the hammer = $a = \frac{v}{t}$

⇒ $a = \frac{10}{0.005} = 2000 m/s^{2}$

Now, the force with which the hammer strikes the nail

= F = ma

= 1.5 Kg × 2000 m/s²

= 3000 N

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