A 1.5m tall boy is standing at some distance from a 30 m tall building.The angle of elevation from his eyes to the top of the building increases from 30° to 60° as he walks towards the building.Find the distance he walked towards the building.
Answers
Answered by
1
Answer:
AB= 30-1.5=28.5 cm
In ΔABD:−tan30
∘
=
BD
AB
⇒BD=(28.5)
3
In ΔABC:−tan60
∘
=
BC
AB
⇒BC=
3
(28.5)
CD= BD-BC
=28.5(
3
−
3
1
)
=28.5(
3
2
)=32.91m
Answered by
1
Answer:
AB= 30-1.5=28.5 cm
In ΔABD:−tan30
∘
=
BD
AB
⇒BD=(28.5)
3
In ΔABC:−tan60
∘
=
BC
AB
⇒BC=
3
(28.5)
CD= BD-BC
=28.5(
3
−
3
1
)
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