a 1.5V battery is connected to a light globe of resistance 2.0W. How many electrons leave the battery in 1 minute
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Heya mate
Here is the answer:--
V= 1.5V
P= 2 W
We know,
P=VI
so, I= P/V
I= 2/1.5
I= 1.3 A
And time,t = 1min = 60 sec
So ,
I=ne/t (n= no. of electron and e=charge on 1 electron)
Putting all values in the formula
1.3= n*1.6*10^-16 / 60
n= 4.875*10^17 (n= number of electrons)
______________
Hope it helps✌✌
Thanks!!
Here is the answer:--
V= 1.5V
P= 2 W
We know,
P=VI
so, I= P/V
I= 2/1.5
I= 1.3 A
And time,t = 1min = 60 sec
So ,
I=ne/t (n= no. of electron and e=charge on 1 electron)
Putting all values in the formula
1.3= n*1.6*10^-16 / 60
n= 4.875*10^17 (n= number of electrons)
______________
Hope it helps✌✌
Thanks!!
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