Question

A(1, 6) and B(3, 5), find the equation of
the locus of point P such that segment
AB subtends right angle at P. (m angle APB=90°)​

Answer 1

Step-by-step explanation:

Let P(x. y) be the point on the locus, A(5. 0) be the point

Distance of point from y-axis = x

Given: AP = x

∴ AP² = x²

∴ [(x – 5 )² + (y – 0)² ] = x²

∴ x ² – 10x + 25 + y ² = x²∴ – 10x + 25 + y ² = 0

∴ y ² – 10x + 25 =0

Hence required equation of the locus is y ² – 10x + 25 = 0