Question

a(-1,7), b(2,7) c(2,11) d(-1,11) find perimeter of abcd
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Answer 1

Answer:

the perimeter is 14.

Explanation:

d(a,b) = 3 (by distance formula)

d(b,c) =4 (ditto)

d(c,d) = 3 (same)

d(a,d) =4 (ditto)

distance formula = √ (x2 - X1)² + (y2 - y1)²

d(a,b) = √ (2- -1)²+ (7-7)² = √3² = 3

d(b,c) = √(2-2)²+ (11-7)²= √4²=4

d(c,d) = √(-1-2)² +(11-11)² = √-3² = 3

d(a,d) = √(-1 - {-1})²+(11-7)² = √4² =4