Question

A 1.75 m heighted weight-lifter raises weights with a mass of 50 kg to a height of 0.5m above his head. How much work is being done by him? (g=10ms)

A 2125 J

B. 2500 J

C. 50 J

D. 1225 J​

Answer 1

Explanation:

Work done by lifting the obj is stored as potential energy

And

$potential \: \: energy = \: mgh$

Here. mass of object = 50 kg

Total height lifted = 1.75 + 0.5 = 2.25 m

$work \: \: done \: = potiential \: \: energy \: \\ = \: mgh \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ = 50 \times 10 \times 2.25 \: \\ = 1125 \: \: joule \: \: \: \: \: \: \: \:$

Answer 2

Work done by lifting the object is stored as potential energy

Here. mass of object = 50 kg

Total height lifted = 1.75 + 0.5 = 2.25 m

g = 10ms

Potential energy = work done = mgh

= 50 * 10 * 2.25

= 1125 joule

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