A 1.84 kg school bag hang in the middle of a clothesline causing it to sag by an angle 3.50° . find the tension in the clothesline
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Answer:
Sum of forces in the x-direction and y-direction are both zero. We are more interested in the y-direction. The clothesline can be thought of as two Tensions (T) at the slight angle - but use 3.5 deg, not 1.8 deg.
2Tcos(theta) = mg
T = mg / 2cos(theta) = 1.84 kg (9.8 N/kg) / 2cos(3.5 deg) = 150 N
Explanation:
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Answered by
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Answer:
T=147.6 N
Explanation:
m= 1.8 kg
g= 9.8
theta = 3.50
T=?
formula ; 2Tsin(theta)=mg
as we have to find T
T =mg/2sin(theta)
solution ;
T= (1.84)(9.8)/ 2sin(3.50)
T= 147.6N
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