Question

(a-1) (a+1) (a^2+1) (a^+1) (a^8+1)= ?​

Answer 1

I hope this answer helps you.

Answer 2

Answer:

Formulae used:

(a+b)(a-b)=(a^2-b^2)

therefore

[(a-1)(a+1)](a^2+1)(a^4+1)(a^8+1)

=[(a^2-1)(a^2+1)](a^4+1)(a^8+1)

=[(a^4-1)(a^4+1)](a^8+1)

=[(a^8-1)(a^8+1)]

=(a^16-1)

Hope it helps