Question

(a+1) (a-1) (a²+1) please solve this problem

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Answer 1

Answer:

a⁴-1

Step-by-step explanation:

We have been given the expression:-

(a+1)(a-1)(a^{2}+1)(a+1)(a−1)(a

2

+1)

Using the identity a^{2} - b^{2}= (a+b)(a-b)a

2

−b

2

=(a+b)(a−b) :-

= (a^{2} - 1^2)(a^{2}+1)(a

2

−1

2

)(a

2

+1)

= (a^{2} - 1)(a^{2} + 1)(a

2

−1)(a

2

+1)

Again using the identity a^2 - b^2 = (a+b)(a-b)a

2

−b

2

=(a+b)(a−b) :-

= [(a^{2})^{2} - 1^{2}][(a

2

)

2

−1

2

]

= (a^{4} - 1)(a

4

−1)

So, it can be evaluated to (a^{4} - 1)(a

4

−1)