A + 1/a = 1 ho to a cube+ 1 =
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take LCm
=> a^2 + 1 = a
=> a^2 +1 - a = 0-----①
NOW, a^3 + 1 = (a+1)(a^2+1-a) = 0(a+1) = 0 [BY ①]
=> a^2 + 1 = a
=> a^2 +1 - a = 0-----①
NOW, a^3 + 1 = (a+1)(a^2+1-a) = 0(a+1) = 0 [BY ①]
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Answer:
Refer to the attachment.
Step-by-step explanation:
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