a+1/a=1, than a³+1=?
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Step-by-step explanation:
a + (1/a)=1
(LCM)
(a²+1)/a=1
Cross multiplying
a²+ 1=a
a²+1-a=0. (equation1)
We have to find
a³+1
a³+ (1)³
using algebraic Identity
x³ + y³=(x + y) (x²+y²- xy)
(a+1) a²+1-a)
by equation 1
(a+1) (0) =0
Therefore a³+1=0. (Ans)
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