Question

a+1/a =1 then a^3+1=?​

Answer 1

Answer:

a+1/a = 3. eq(1)

taking cube on both sides then eq(1) becomes

(a+1/a)^3 = 3^3

by using the formula

[ (a + b)^3 = a3 + 3ab(a+b) + b3 ]

a3 + 3(a)(1/a)(a+1/a) + (1/a)^3 = 9

a3 + b3 +(a+1/a) = 9

As we know that. (a+1/a)= 3

so,

a3 + 1/a3 +3(3) = 9

a3 +1/a3 + 9 = 9

a3+1/a3 = 9-9

a3+1/a3 = 0 ✓✓ [SOLVED]

HOPEFULLY THIS SOLUTION WILL HELP YOU

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

a+(1/a) = 1. ( given)

taking LCM

(a^2 + 1)/a = 1

a^2 + 1 = a

a^2 - a +1= 0

by using shridarachaya formula

we get two roots

so, a= {-b+-√( b^2-4ac)}/2a

={-(-1)+-√((-1)^2-4×1×1}/2×1

={1+-√-3}/2

here D which is discriminant is √-3

which define the roots are imaginary .

so there is no real solution for this question.