a+1/a=1 then a^3+1=??
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ElitmusExamNumerical AbilityNumber System
Q If a+1/a=1 then a3=?
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Given a+1/a=1
multiply with a^2 both sides
a^3+a=a^2_______(1)
=>a(a^2+1)=a^2
=>a^2=a-1;
now from 1, a^3=a^2-1=>a^3+a=a-1=>a^3=-1
6 years agoHelpfull: Yes(23) No(8)a+1/a=1,
a^2+1=a;
a^2-a+1=0;
(a+1)(a^2-a+1)=(a+1)*0;
a^3+1=0;
a^3=-1;
6 years agoHelpfull: Yes(17) No(0)Since a+1/a=1, we can 1/a=1-a ---- assume equation (1)
Now, taking square on both side
we get
a^2 + 1/a^2 + 2=1
a^2 + 1/a^2 = -1 put the value of 1/a form equation (1)
a^2 + (1-a)^2=-1
a^2 + 1 + a^2 -2*a=-1
2*a^2 - 2*a=-2
a^2 - a =-1
a(a-1)=-1
a=-1,0
Here a=0 mean, there is no meaning
so, finally a=-1
and Answer is: a^3=-1
6 years agoHelpfull: Yes(13) No(9)a+1/a=1
a^2+1=a => a^2=a-1
a^2-a+1=0
multiplying and devide by a
a^3-a^2+a=0
a^3=a^2-a
a^3=a-1-a
a^3=-16 years agoHelpfull: Yes(4) No(3)(a+1)/a=1
(a+1)^2=a^2
a^2+2a+1=a^2
2a=-1
a=-1/2
a^3=-1/8 ans6 years agoHelpfull: Yes(3) No(7)(a+1/a)=1
Step-by-step explanation:
I hope that helps you