a+1/a=1 then a3+1=?
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Answer:
a^2+1=a
a^2-a+1=0
a=1+root3/2
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a³ + 1 = 0.
Given - a+1/a=1
Find - a³ + 1
Solution - Firstly multiplying the equation in question with variable 'a'.
a² + 1 = a
a² = a - 1 - equation 1
Again multiplying equation 1 with variable 'a' to find a³.
a³ = a(a - 1)
Now, from the original equation -
a - 1 = -1/a
Keep the value of (a - 1) in above equation.
a³ = a*(-1/a)
a³ = -1
Now, the value of a³ + 1
Keep the value of a³
Value = -1 + 1
Value = 0
Hence, a³ + 1 is 0.
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