Question

a+1/a=17/4 find the value of(a-1/a)

Answer 1

a+1/a=17/4
$({a + \frac{1}{a} })^{2} = (\frac{17}{4} ) ^{2}$
${a }^{2} + \frac{1}{ {a}^{2} } + 2 = \frac{289}{16}$
${a}^{2} + \frac{1}{ {a}^{2} } = \frac{289}{16} - 2$
${a}^{2} + \frac{1}{ {a}^{2} } = \frac{257}{16}$
${a}^{2} + \frac{1}{ {a}^{2} } - 2 = \frac{257}{16} - 2$
$({a - \frac{1}{a} })^{2} = \frac{225}{16}$
$(a - \frac{1}{a} ) = \frac{15}{4}$

Answer 2

Answer:

$(a+a1)2=(417)2 </p><p>{a }^{2} + \frac{1}{ {a}^{2} } + 2 = \frac{289}{16}a2+a21+2=16289 </p><p>{a}^{2} + \frac{1}{ {a}^{2} } = \frac{289}{16} - 2a2+a21=16289−2 </p><p>{a}^{2} + \frac{1}{ {a}^{2} } = \frac{257}{16}a2+a21=16257 </p><p>{a}^{2} + \frac{1}{ {a}^{2} } - 2 = \frac{257}{16} - 2a2+a21−2=16257−2 </p><p>({a - \frac{1}{a} })^{2} = \frac{225}{16}(a−a1)2=16225 </p><p></p><p></p><p>(a - \frac{1}{a} ) = \frac{15}{4}(a−a1)=415 </p><p>$