Question

(a+1/a)²+(2a–3/a)²=?​

Answer 1

Answer:

(a+1/a)^2+(2a-3/a)^2

(a^2+1/a^2+2)+(4a^2+9/a^2-12)

{since, (a+b)^2 = a^2+b^2+2ab)

a^2+1/a^2+2+4a^2+9/a^2-12

5a^2+(1/a^2+9/a^2)-10

5a^2+10/a^2-10

5{a^2+2/a^2-2}

that's all

thank you.