Question

(a+1/a)^2 =3, then a^3+1/a^3=?​

Answer 1

Answer:

Step-by-step explanation:

By above equation (a+1/a) ^2=3

So the value of a+1/a becomes √3

(A+1/A)³ =A³+1/A³+3(A) *(1/A) (A+1/A) = 3³

BY SUBSTITUTING VALUE OF (A+1/A)

WE GET

A³+1/A³+3(√3) =3³

A³+ 1/A³=27-3√3

=3√3(1-3√3)

Answer 2

Step-by-step explanation:

Brainly.in

What is your question?

Primary School Math 5 points

If (a+1/a)^2=3 then show that a^3+ 1/a^3= 0.

Ask for details Follow Report by Jolly13 30.03.2018

Answers

Utkarrshh

Utkarrshh Ace

a^3 +b^3 = a^2 - ab + b^2

(a^3+ 1/a^3) = ( a+ 1/a) ( a^2 -1 +1/a^2) (1) equation

it is given that

(a+1/a)^2 = 3

or

( a+ 1/a) = √3. (2) equation

Also

( a+ 1/a)^2 = 3

or - a^2 + 1/a^2 +2 =3

then ( transpose 2 to subtract 3)

a^2 + 1/a^2 = 3-2

a^2 + 1/a^2 = 1. (3) equation

putting 2 and 3 in 1 we have

a^3 +1/a^3 = √3 (1-1) = 0

so the answer is 0

hope it helps

thank you