Question

(a+1/a)^2 -(a-1/a)^2

Answer 1

Answer:

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Answer 2

Answer:

4

Step-by-step explanation:

Use

$a^2-b^2=(a-b)(a+b)$

$\left(a+\dfrac{1}{a}\right)^2-\left(a-\dfrac{1}{a}\right)^2=\left[a+\dfrac{1}{a}-\left(a-\dfrac{1}{a}\right)\right]\left(a+\dfrac{1}{a}+a-\dfrac{1}{a}\right)\\\\=\left(a+\dfrac{1}{a}-a+\dfrac{1}{a}\right)(2a)=\left(\dfrac{2}{a}\right)(2a)=\dfrac{4a}{a}=4$