Math, asked by sknazmuddin21, 1 month ago

(a+1/a)²+(a-1/a)².solution​

Answers

Answered by Anonymous
1

Hope it helps...

thanks...

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Answered by kamalhajare543
7

Answer:

Answer:

As, (a+b)²=a²+2ab+b²

(a–b)²=a²–2ab+b²

 \sf \: ( a + \frac{1}{a} )^{2} - (a - \frac{1}{a} )^{2}

\sf \implies \bigg [\frac{a ^{2} + 1}{a} \bigg] {}^{2} -   \bigg[\frac{a {}^{2} - 1}{a} \bigg]  {}^{2}

\sf \implies \bigg [\frac{(a {}^{2} + 1) {}^{2} }{a {}^{2} }  \bigg] \bigg [ \frac{ ({a}^{2} + 1) {}^{2} }{a {}^{2} }  \bigg] \sf

[] \sf \implies

  \sf \implies\sf \: =\frac{a {}^{4} + 2a {}^{2} + 1}{a {}^{2} } -  \bigg[ \frac{a {}^{4} - 2a {}^{2} + 1 }{a {}^{2} }  \bigg]

 = \sf \: \frac{ {a}^{4} + 2a {}^{2} + 1 - {a}^{4} +2a {}^{2} - 1 }{a {}^{2} }\\   \\ \sf \: =\frac{4a {}^{2} }{a {}^{2} }

= 4

Hence This Is Answer.

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