Question

a+1/a=34 then root a +1/root a=

Answer 1

Answer:

6

Step-by-step explanation:

Answer 2

The value of $\sqrt{a} +\dfrac{1}{\sqrt{a} }$  is 6

Step-by-step explanation:

Given: $a+\dfrac{1}{a}=34$

To find: The value of $\sqrt{a} +\dfrac{1}{\sqrt{a} }$

Now as we know

$(a+b)^2 = a^2+b^2+2ab$

So we have

$(\sqrt{a} +\dfrac{1}{\sqrt{a} })^2=(\sqrt{a} )^2+(\dfrac{1}{\sqrt{a} })^2+2\times\sqrt{a} \times \dfrac{1}{\sqrt{a} }\\\\\Rightarrow (\sqrt{a} +\dfrac{1}{\sqrt{a} })^2= a+\dfrac{1}{a} +2$

substitution the value of  $a+\dfrac{1}{a}=34$

we get

$\\\\\Rightarrow (\sqrt{a} +\dfrac{1}{\sqrt{a} } )= 32+2\\\\\Rightarrow (\sqrt{a} +\dfrac{1}{\sqrt{a} } )=36\\\\\Rightarrow \sqrt{a} +\dfrac{1}{\sqrt{a} } =\sqrt{36} \\\\\Rightarrow \sqrt{a} +\dfrac{1}{\sqrt{a} } =6$

Hence ,the value of $\sqrt{a} +\dfrac{1}{\sqrt{a} }$  is 6

#Learn more

a+1/a=17/4 find (a-1/a)

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