Question

a-1/a=8 a+1/a a^2-1/a^2

Answer 1

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Answer 2

Hope u like my process
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$= > a - \frac{1}{a} = 8 \\ \\ \bf \underline{squaring \: \: both \: \: sides} \\ \\ = > {(a - \frac{1}{a}) }^{2} = {8}^{2} \\ \\ = > {(a - \frac{1}{a} )}^{2} + 4a. \frac{1}{a} = 64 + 4 \\ \\ = > {(a + \frac{1}{a}) }^{2} = 68 \\ \\ = > \bf \: a + \frac{1}{a} = \underline{ \sqrt{68} } \\ \\ \underline{ now } \\ \\ = > {a}^{2} - \frac{1}{ {a}^{2} } \\ \\ = > (a + \frac{1}{a} )(a - \frac{1}{a} ) \\ \\ = > 8 \times \sqrt{68} = \bf \underline{ 8 \sqrt{68} }$
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