Question

a+ 1/a = 8. Ford a2+ 1/a2​

Answer 1

According to question,

a + 1/ a = 8

find a2 + 1/a2

Now ,

$a + \frac{1}{a } = 8$

squaring both side ,

$(a + \frac{1}{a}) ^{2} = {8}^{2}$

here we will use the formula of,

$(a + b {})^{2} = {a}^{2} + 2ab + {b}^{2}$

Now ,

${a}^{2} + \frac{1}{ {a}^{2} } + 2.a. \frac{1}{a} = 64$

${a}^{2} + \frac{1}{a {}^{2} } = 64 - 2$

${a}^{2} + \frac{1}{ {a}^{2} } = 62$

Answer 2

AnswEr :

$\large\Rightarrow \tt{a + \frac{1}{a} = 8 }$

☢ Squaring Both Side

$\large\Rightarrow \tt {(a + \frac{1}{a}) }^{2} = {8}^{2}$

$\large\Rightarrow \tt{ {a}^{2} + { \frac{1}{ {a}^{2} }} + 2 \times a \times \frac{1}{a} } =( 8 \times 8)$

$\large\Rightarrow \tt{ {a}^{2} + \frac{1}{ {a}^{2} } = 64 - 2 }$

$\huge\Rightarrow \tt{ {a}^{2} + \frac{1}{ {a}^{2} } = 62 }$