Question

A
1. A trolley of mass 1 kg is connected to two
identical spring of spring constant 100 N/m each.
If trolley is displaced from mean position by 1 cm
then maximum velocity of trolley is
(
1
)
mm
mm
(1) 0.01 m/s
(3) 0.14 m/s
(2) 1.4 m/s
(4) 14 m/s
motions are represented by​

Answer 1

Explanation:

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option 2

Answer 2

Answer:

Maximum velocity v =?

given, mass of trolley,m = 1 kg

spring constant k = 100 N / m

displacement of trolley

X = 1 cm = 10^- 2 m

there are two springs connected in series so the net spring constant KnET = 100+ 100=200N/m

as we know that,

time period T = 2πsqrt mass/ net spring constant

T = 2πsqrt 1/200

T = sqrt2π/10 sec

now, maximum velocity=xw = x 2π/ t

# v = 10 ^ -2 2π/sqrt2π/10

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