Question

[a^-1 b^2/a^2 b^-4]^7÷[a^3 b^-5/a^-2 b^3]^-5​

Answer 1

Answer:

a^-8b¹⁴

Step-by-step explanation:

Let a=x and b=y

$({x}^{ - 1 - 2} {y}^{2 - ( - 4)} ) \div ( {x}^{3 - ( - 2)} {y}^{ - 5 - 3}) \\ {x}^{ - 3} {y}^{6} \div {x}^{5} {y}^{ - 8} \\ {x}^{ - 8} {y}^{14}$