Question

A 1 μc charge is 5 cm away from a -2 μc charge. what is the magnitude and direction of the force on the 1 μc charge

Answer 1

Just apply Coulomb's law.
F = 1/4πε₀ q₁q₂/r²
F = 9x10⁹ x 17x10⁻⁶ x
2.8x10⁻³ / (0.37)² =
3129.29N

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Answer 2

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The given figure shows a square of side 10 cm with four charges placed at its corners.

O is the centre of the square.

Where,

(Sides) AB = BC = CD = AD = 10 cm

(Diagonals) AC = BD = cm

AO = OC = DO = OB = cm

A charge of amount 1μC is placed at point O.

Force of repulsion between charges placed at corner A and centre O is equal in magnitude but opposite in direction relative to the force of repulsion between the charges placed at corner C and centre O.

Hence, they will cancel each other.

Similarly, force of attraction between charges placed at corner B and centre O is equal in magnitude but opposite in direction relative to the force of attraction between the charges placed at corner D and centre O.

Hence, they will also cancel each other.

Therefore, net force caused by the four charges placed at the corner of the square on 1 μC charge at centre O is zero.

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