Question

a=1, d=1/2 . find first four terms of ap​

Answer 1

a=1

d=1/2

a2=1+1/2

= 3/2

a3=3/2+1/2

= 4/2 =2

a4=2+1/2

= 5/2

the first four terms of an ap is 1,3/2,2,5/2

Answer 2

A1 = 1

A2 = a+(n-1)d = 1+½ = 3/2

A3= a+2d = 1+1=2

A4=a+3d = 1+3/2 = 5/2

Therefore, the first four terms of the ap are

1, 3/2, 2, 5/2

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