Question

A 1 H inductance carrying a current of 3 A will stor energy of?

Answer 1

Given:

Inductance $=L=$ 1 Henry

Current $=I=$ 3 Amperes

To find:

We need to find the energy stored in the coil.

Solution:

We know that, the energy stored in an inductor or coil is given by the formula

$E = \frac{1}{2 }LI^2$

Where $L$ is the inductance of the coil and $I$ is the current through the coil.

Now, substitute the values of Inductance $L$ and Current $I$ given in the question in the above formula.

$\Rightarrow E = \frac{1}{2 }LI^2$

$\Rightarrow E = \frac{1}{2 }\times1\times(3)^2$

We know that, $(3)^2=9$.

$\Rightarrow E = \frac{1}{2 }\times1\times9$

Simplifying the terms in Right Hand Side,

$\Rightarrow E = \frac{1}{2 }\times9$

$\Rightarrow E = \frac{9}{2 }$

$\Rightarrow E = 4.5$

The units of energy is Joules.

$\Rightarrow E = 4.5$ Joules

Therefore, the energy stored in the coil is $4.5$ Joules.