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1 If z= x+iy and |z + 6|= |2z + 3|, prove that, x2 + y2 = 9
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Answer:
z^2+36+12z=4z^2+12z+9
3z^2-27=0
z^2=9
(x+iy)2=9
x^2-y^2 +2ixy=9+i×0
x^2-y^2=9 and 2xy=0 and xy=0
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