Question

A 1 kg ball falls from height of 64 cm and rebounds upto a height of 16 cm.the coeficient of restiution is

Answer 1

coefficient of restitution will be less than 1

Answer 2

Answer:

The coefficient of restitution is $e=\dfrac{1}{2}$

Explanation:

Given that,

Height h = 64 cm

Rebound height = 16 cm

We need to calculate the coefficient of restitution

The initial velocity is

$u^2=2gh$

$u=\sqrt{2gh}$

$u =\sqrt{2g\times64}$

The final velocity is

$v^2=2gh$

$v=\sqrt{2gh}$

$v=\sqrt{2g\times16}$

The coefficient of restitution is defined as:

$e = \sqrt{\dfrac{v}{u}}$

$e=\sqrt{\dfrac{2g\times16}{2g\times64}}$

$e={\dfrac{1}{2}}$

Hence, The coefficient of restitution is $e=\dfrac{1}{2}$